makefile

#include "mylib.h"
int main(int argc, char* argv[]){
	char *g;
	g = "hello\n";
	cout(g)
}

void cout(char* str)

#include <stdio.h>
void cout(char* str){
	printf("%s",str);
}

all: compile link
	./a.out
compile: main.c prints.c
	gcc -c main.c
	gcc -c prints.c
link: compile
	gcc main.o prints.o

• all –depends-on–> compile link
  • compile –depends-on–> main.c prints.c
    • link –depends-on–> compile

Notice the only atomic or leaf dependencies are main.c prints.c

• mylib.h behaves like an interface, it holds the interface or placeholder of function cout
• How does mylib.h know cout function is located in prints.c?
  • ANSWER: It doesn’t, the Makefile is what links the placeholder of cout to it’s implementation in compiled prints.o

Static analysis to find dependencies doesn’t work without also analyzing the Makefile linking the object files.
Doxygen tells you that a function like cout exists somewhere but we dont know how or where it is implemented.